The arrows shot by the three archers hit a tree as shown below. Arrow A and B are in parallel to the ground and arrow C cuts across the other two arrows. If the longer angle made by arrow A and C is 150°, What is the angle at which the third archer launched arrow C?
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Given;
A and B are parallel to the ground.
C crosses A and B.
C crosses A at an angle of 150⁰°.
So, considering the corresponding angles C crosses B at an angle of 150°.
[Since, correspondent angles are equal]
For reference, check the image at the attachment. 2, 6 are the required correspondent angles.
Therefore, considering the alternate angles, the third archer launched arrow C at 30°.
In the image at the attachment, the alternate angles are 1 and 7. Launching the arrow on the tree, angle 7 will be angle of launch.
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