Math, asked by hiabhinav, 1 month ago

The arrows shot by the three archers hit a tree as shown below. Arrow A and B are in parallel to the ground and arrow C cuts across the other two arrows. If the longer angle made by arrow A and C is 150°, What is the angle at which the third archer launched arrow C?

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Answered by Anonymous
6

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Given;

A and B are parallel to the ground.

C crosses A and B.

C crosses A at an angle of 150⁰°.

So, considering the corresponding angles C crosses B at an angle of 150°.

[Since, correspondent angles are equal]

For reference, check the image at the attachment. 2, 6 are the required correspondent angles.

Therefore, considering the alternate angles, the third archer launched arrow C at 30°.

In the image at the attachment, the alternate angles are 1 and 7. Launching the arrow on the tree, angle 7 will be angle of launch.

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