Question

The ascending order of 3root2 , 2 root8, 4 root 3

Answer 1

Answer:

$number : \\ 3 \sqrt{2} \: \: \: \: 2 \sqrt{8} \: \: \: \: 4 \sqrt{3} \\ square \: all \: the \: number \: we \: get \\ {(3 \sqrt{2)} }^{2} = 9 \times 2 = 18 \\ {(2 \sqrt{8}) }^{2} = 4 \times 8 = 28 \\ {(4 \sqrt{3)} }^{2} = 16 \times 3 = 48 \\ arrenge \: them \:$