The assembly hall of a hotel is 55 m long ,45 m broad and 10 m high . It has 5 windows 3m by 1.5 m each and three doors of 3 m by 2 m each . Find the cost of (a) decorating the wall at the rate of ₹15 per m^2 (b) carpeting the floor at the rate of ₹30 per m^2 (c) painting the ceiling at the rate of ₹20 per m^2
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Answer:
The cost of painting the wall is Rs 29392.50, The cost carpeting the floor is Rs 74250, the cost of painting the ceiling is Rs 49500
Step-by-step explanation:
The assembly hall has four walls. so, we need to get the surface area of the four walls.
The surface area of the walls is given by:
= 2(55 × 10) + 2(45 × 10) = 1100 + 900 = 2000 m²
The hall has 5 windows and 3 doors. Therefore, we need to get the area of the remaining parts of the walls.
Area of a window = 3 × 1.5 = 4.5 m²
Total area of the windows = 4.5 m² × 5 = 22.5 m²
The area of a door = 3 × 2 = 6 m²
The area of the doors = 6 × 3 = 18 m²
So the area to be painted is = 2000 - (18 + 22.5) = 1959.50 m²
The cost of painting the walls = 1959.50 × 15 = Rs 29392.50
b) The area of the floor is:
55 × 45 = 2475 m²
The cost of carpeting the floor is:
= 2475 × 30 = Rs 74250
c) The area of the ceiling = the area of the floor = 2475 m²
The cost of painting the ceiling is:
= 2475 × 20 = Rs 49500