Question

The assembly hall of a hotel is 55 m long, 45 m broad and 10 m high. It has 5 windows 3 m by 1.5 m each and three doors of 3 m by 2 m each. Find the cost of: (i) Decorating the walls at the rate of 15 per (ii) Carpeting the floor at the rate of 730 per m² (iii) Painting the ceiling at the rate of 520 per m? ? 135 cm2 resnectively, then find m2​

Answer 1

Answer:

Given, length of hall, 1= 45 m Breadth of hall, b= 30 m And height of hall, h= 16 m Then, area of four walls of the hall = 2(1+ b) × h = 2(45+ 30) × 16 = 2 x 75 x 16 %3D %3| = 2400 m? Dimensions of each door is 4 m by 3.5 m. Therefore, area of five doors = 5 x (4 x 3.5) = 70 m? Also, dimension of each window is 2.5 m by 1.6 m. Therefore, area of four windows = 4 x (2.5 x 1.6) 16 m2 Thus, area to be papered = Area of four walls -(Area of five doors + Area of four windows) = 2400 – (70 + 16) = 2400 – 86 = 2314 m2 Now, cost of papering 1 m2 = Rs. 35 So, cost of painting 2314 m2 = Rs. (35 x 2314) = Rs. 80990