Question

The atmospheric pressure at a place is 10^5 Pa. If Tribromomethane (specific gravity = 2.9) be employed as the barometric liquid,the barometric height is (1) 3.52 (2) 1.52 (3) 4.52 (4) 2.52

Answer 1

Answer:

Option (1) 3.52 m

Explanation:

Atmospheric pressure = $10^5$ Pa = $10^5$ N/m²

Density of triboromethane $\rho=2.9\times 10^3$ kg/m³

The liquid will rise to a height so as to the pressure is equal to the atmospheric pressure

Let the height be h

Then

$\rho\times g\times h=10^5$

$\implies h=\frac{10^5}{\rho\times g}$

$\implies h=\frac{100\times 10^3}{2.9\times 10^3\times 9.8}$

$\implies h=\frac{100}{2.9\times 9.8}$ m

$\implies h=3.52$ m

Hope this helps.

Answer 2

ρ×g×h=10

5

\implies h=\frac{10^5}{\rho\times g}⟹h=

ρ×g

10

5

\implies h=\frac{100\times 10^3}{2.9\times 10^3\times 9.8}⟹h=

2.9×10

3

×9.8

100×10

3

⟹h= 2.9×9.8

100

s h=3.52⟹h=3.52 m