Question

The atom A and B have electronic configuration (2,8,18,2) and (2,6)
i) Which atom is likely to form cation.
ii)Which atom is likely to form anion.
iii)What will be the valency of A.
iv)What is the formula of the compound between A and B.​

Answer 1

Answer:

1- atom A .2- atom B 3- A=+2 . 4 - AB

Explanation:

1. its atomic number is 30 so it can lend 2 electrons and complete octet E. C.
2. it gains 2 electrons and gets negative charge
3. +2 ( same answer as 1)
4. AB because +2 , -2 gets simplify and become 0

Answer 2

Answer:

i) Atom likely to form cation = A

ii) Atom likely to form anion = B

iii) The valency of A = 2

iv) The formula of the compound between A and B = AB

Explanation:

i) An ion with positive charge is called a cation. When an atom loses one or more electrons from its outermost shell, the number of protons will become greater than the number of electrons. Hence the atom becomes positively charged and it becomes a cation.

Here atom A with electronic configuration (2,8,18,2) is likely to form cation because, the outermost shell of atom A, contains 2 electrons, and hence it has a tendency to loose 2 electrons and form $A^{2+}$ions.

ii) An ion with negative charge is called an anion. When an atom gains one or more electrons, the number of electrons in the atom will become more than the number of protons. Hence the atom becomes negatively charged and it becomes an anion.

Here the atom with electronic configuration (2,6) is likely to form an anion because the outermost shell of this atom contains 6electrons and hence it has a tendency to gain electrons and form $B^{2-}$ ions.

iii) The valency of an atom is defined as the combining capacity of the atom to form compounds. Hence the valency of A = 2

iv) When a compound is formed between A and B, atom A loses two electrons and atom B gains two electrons.

The formula of the compound formed = AB

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