the atom of an element has 9 protons 9 electrons and 10 neutrons, find atomic number,mass number, electronic configuration, valance, valance electrons, metal or nonmetal, cathode and anode,period, group
Answers
Answer:
REFER BELOW
Explanation:
The element is Flourine
It has Atomic Number 9
Mass Number is 19
Electronic Configuration - 2,7
Valencey - 1
Valence Electrons - 7
It is a non Metal
Answer:
the atomic number is 9.
mass number = 10+9 = 19
electronic configuration = 1S² 2S² 2P⁵
valency is 1.
valance electrons here is 7.
non-metal.
cathode.
It belongs to the 2nd period (2S 2P) and (7+10) 17th group of the periodic table.
Explanation:
The given data is that the element has 9 electrons, 9 protons, and 10 neutrons
So, the number of protons or the number of electrons is equal to the atomic number of the element. Hence here the atomic number is 9.
The mass number of the element is equal to the number of protons+ number of neutrons. So, here mass number = 10+9 = 19
From the number of electrons, electronic configuration = 1S² 2S² 2P⁵
Here outer shell is 2S it has 7 electrons hence it needs one more electron to complete the octet. Therefore valency is 1.
The number of valance electrons here is 7.
From the above data, the element is fluorine.
Fluorine is a non-metal.
Fluorine always acts as a cathode.
It belongs to the 2nd period (2S 2P) and (7+10) 17th group of the periodic table.