Question

The atomic mass of Na is 23u and edge legth of unit cell is 430pm. If the density of sodium is 0.9623g/cm3 what type of unit cell is formed by Na?

Answer 1

Answer:

Calculate the number of atoms in the unit cell. (Atomic mass Na = 23 amu, Density of Na = 0.9623 g cm-3) z=(0.9623g cm-3)×(430)3×(6.022×1023mol-1)×(10-30cm3)(23 gmol-1)=2(bcc structure).