Question

The atomic masses of he and ne are 4 and 20

a.m.u., respectively. the value of the de broglie wavelength of he gas at --73∘∘c is 'm' times that of the de broglie wavelength of ne at 727∘∘c. m is

Answer 1

Dear Student,

Please find below the solution to the asked query:

As we know that, λ=hp=hmV=h2M K.E.√⇒ λ∝1MT√ [Since K.E. ∝T ]Hence, for two gases,λHeλNe=MNeTNeMHeTHe−−−−−−√=20×10004×200−−−−−−√=5Hence, λHeλNe=5

Hence the ratio of de-Broglie wavelength i.e. λHe : λNe = 5 : 1

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