Question

the atomic number of an element is 35 & mass number is 81 the number of electrons in the outer most shell will be??????

Answer 1

Electrons in outermost shell will be 7
having electron configuration
2, 8, 18, 7

Thanks

Answer 2

Answer: The electrons present in the outermost shell of the given element is 7

Explanation:

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

We are given:

An element having atomic number = 35

Mass number = 81

Number of electrons = Number of protons = 35

Valence electrons are defined as the electrons that are present in the outermost shell of an element. The shell having highest value of principle quantum number that is 'n' is the valence shell.

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Electronic configuration of element having 35 electrons = $1s^22s^22p^63s^23p^64s^23d^{10}4p^5$

The electrons present in n = 4 shell (outermost shell) are 7

Hence, the electrons present in the outermost shell of the given element is 7