Question

The atomic number of oxygen is 8 a)represent the bonding in oxygen molecules using electron dot diagram? b)which type of bond is present in it?

Answer 1

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HERE IS YOUR ANSWER ⬇ ⬇

A) It is in the attachment

B) Type of bond is present in oxygen is Covalent because non-metal and non-metal forms covalent bond

HOPE IT HELPS !!!!!!

Answer 2

Answer:

In oxygen molecule, the bond formed between the oxygen atoms is double bond.

Explanation:

• The atomic number of oxygen is 8. The electronic configuration of oxygen is : 1s² 2s² 2p⁴.
• Oxygen atom has 8 electrons . In oxygen molecule we have two atoms . Therefore, total 16 electrons in oxygen molecule.
• The molecular orbitals are formed by the overlapping of atomic orbitals. Therefore, number of molecular orbitals will be equal to number of atomic orbitals.
• On the basis of molecular orbital theory the electronic configuration of oxygen molecule is:

       $\sigma1s^2\; \sigma^*1s^2\; \sigma2s^2\; \sigma^*1s^2 \; \sigma2p_{z}^2\; \;\pi 2p_{x}^2\;\; \pi 2p_y^2\;\;\pi^* 2p_{x}^1\;\; \pi ^*2p_y^1$

• Bond order  $=\frac{N_a-N_b}{2}$

                              $=\frac{10-6}{2}$

                              $=2$

Therefore, the bond between the oxygen atoms in oxygen molecule is double bond.