The atomic numbers of four elements A, B, C and D are 6, 8, 10 and 12 respectively. The two elements which can react to form ionic bonds (or ionic compound) are :
(a) A and D
(b) B and C
(c) A and C
(d) B and D
Answer : (d) B and D
Please tell the steps to solve this....
Answers
Given :
- Atomic numbers of elements A , B , C and D are 6 , 8 , 10 , 12
To find :
- Two elements which can form an ionic bond
Explanation :
Configuration of element 'A' (Z = 6) is , 1s² 2s² 2p² . It has 2 valence electrons and require 4 more electrons to attain stability.
Configuration of element 'B' (Z = 8) is , 1s² 2s² 2p⁴ . It has 4 valence electrons and require 2 electrons to attain stability.
Configuration of of element 'C' (Z=10) is 1s² 2s² 2p⁶. It has fully filled configuration . Since the atom has acquired stabiliy . The element 'C' won't participate in bond formation.
Configuration element 'D' ( Z = 12) is 1s² 2s² 2p⁶ 3s² . It has two valence electrons . To acquire stability the elemwnt can lose (or) gain electrons. In this case the element 'D' tries to lose two valence electrons and wants to acquire a stable configuration. So , The element 'D' needs to lose 2 electrons.
Now , If we observe the element 'B' it want to gain 2e⁻ and where as element 'D' want to lose 2 e⁻. Now , these two elements 'D' and 'B' can form an ionic bond by losing 2e⁻ and by gaining 2e⁻.
Hence , Option(D) is the required answer.