Question

The atomic numbers of sodium and sulphur are 11 and 16 respectively. How many electrons are present in Na+ and S2– ions?​

Answer 1

Explanation:

The atomic number of sodium is 11. It has 11 electrons. It loses one electron to form sodium ion.

Na→Na

+

+e

−

Then the number of electrons in sodium ion is 11−1=10.

Answer 2

Atomic no of Na=11 hence electrons are 11 too and Na- =12

And atomic no of sulphur is 16 hence there are 16 electrons and S2 will have twice the electrons hence 32 and S2- =31 electrons