Question

The atomic numbers of sodium and sulphur are 11 and 16 respectively. How many electrons are present in Na+ and s^ 2- ?

Answer 1

Answer: $Na^{+}$ ion will have 10 electrons and  $S^{-2}$ ion will have 18 electrons

Explanation:

Given :-
Atomic no. of Sodium ( Na ) and Sulphur ( S ) is 11 and 16 respectively.

We know that,
Atomic no. = No. of protons in one atom of the element = No. of electrons in one atom of the element

We also know that the shells K, L and M have a capacity of holding 2, 8 and 8 electrons respectively.

Since the sodium ion in  $Na^{+} , S^{-2}$ has a positive charge over it, it will lose 1 electron and sulphide ion has a negative charge over it with the valency of 2, it will gain 2 electrons.

Na atom has 11 electrons, $Na^{+}$ ion will have 10 electrons.

S atom has 16 electrons, $S^{-2}$ ion will have 18 electrons.