The atomic numbers of three elements A, B and C are 12, 18 and 20 respectively. State, giving reason, which two elements will show similar properties.
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Answer:
ATOMIC NO.
A = 12
B = 18 , n
C = 20
electronic configuration is,
A = 2,8,2
B = 2,8,8
C = 2,8,8,2
Now, from above , we can conclude that element A and C have similar properties since they are in the same period.
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Answered by
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Element A and C i.e., Magnesium and calcium will show similar properties as they belongs to group 2 metals which are popularly known as alkaline Earth metals and they both have 2 electrons in their valence orbit in s orbital where as, Argon is a nobel gas......
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