Question

The atomic numbers of three elements A, B and C are 4, 8 and 16 respectively. State giving reason which two elements will show similar chemical properties.

Answer 1

Answer:

element with atomic no. 4 (A) = Beryllium

element with atomic no. 8 (B) = Oxygen

element with atomic no. 16 (C) = Sulphur

Oxygen(B) and Sulphur(C) will show similar chemical properties ( like outer electronic configuration, formation of hydrides, etc.) as both of them are in the same group of the periodic table.

Answer 2

Hey friend!

Here is your answer;

We know that the elements in the same group of the periodic table have similar properties. This is because of the similar outer electronic configuration.

To find the similar elements, we need to find the number of outer electron first.

For A, it is 4 - 2 = 2

For B, it is 8 - 2 = 6

For C, it is 16 - 2 - 8 = 6

Hence, the number of outer electrons is same in Elements B and C

Hence they show similar chemical properties


I hope it helps you