Question

The atomic numbers of three lanthanide elements X, Y and Z are 65, 68 and 70 respectively, their Ln3+ electronic configuration is a. 4F8 , 4f11, 4f13 b. 4F11, 4f8 , 4f13 c. 4F0 , 4f2 , 4f11 d. 4F3 , 4f7 , 4f9​

Answer 1

Answer:

the answer to your question is A

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Answer 2

The answer is a. 4$f^8$ , 4$f^{11$, 4$f^{13}$.

Explanation:

The element with atomic number 65 would have an electronic configuration of $[Xe] 4f^9 6s^2$

In the +3 oxidation state, there would be a removal of three electrons, two from 6s- orbital and one from 4f- orbital, hence electronic configuration of $X^{3+$ would become $[Xe] 4f^8$

Similarly, the electronic configurations of Y and Y and their ions would be:

Y( Atomic Number = 68): $[Xe] 4f^{12} 6s^2$ and $Y^{3+}: [Xe] 4f^{11}$

Z( Atomic Number = 70):$[Xe] 4f^{14} 6s^2$ and  $Z^{3+}: [Xe] 4f^{13}$

Hence, option a) would be correct.