The atomic radii of three elements A, B and C of a periodic table are 186 pm, 104 pm and 143
pm respectively. Giving a reason, arrange these elements in the increasing order of atomic
number in the period.
Answers
Answered by
41
Ans-Order of radii is B<C<A.
since atomic size decreases along a period,as the atomic number(nuclear charge) increases thus,the element with smaller radii,has the highest atomic number.
Hence,B has the highest atomic number followed by C and A
i.e. A<C<B
since atomic size decreases along a period,as the atomic number(nuclear charge) increases thus,the element with smaller radii,has the highest atomic number.
Hence,B has the highest atomic number followed by C and A
i.e. A<C<B
Answered by
12
let,
A=186 pm
B=104 pm
C=143 pm
the atomic size decreases along a period, as the atomic number [nuclear charge} increases. THUS, the element with smaller radii has the highest atomic number.
hence, B<C<A
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