Question

The atomic weight of two elements A and B are respectively m and n. One gram vapour of the volatile compound AnBm occupies at S.T.P a volume of.....?​

Answer 1

Explanation:

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Answer 2

Answer:

Volume = 22.4/(m+n)

Explanation:

This can be obtained by the relation,

Number of moles(n) = Given volume(at STP in L) / 22.4(L)

Also number of moles can be determined by the equation,

Number of moles(n) = Given mass/molar mass

Here,

• given mass = 1
• molar mass = m+n

∴ n = 1/(m+n)

In the first equation, we can substitute it,

∴ 1/(m+n) = Volume/22.4

⇒ Volume = 22.4/(m+n)

NOTE: The final answer should be written in litres..