Question

the attractive force between to particles is inversely proportional t o square of distance between them f= k/r^2. initally bodies are at distancw d , an external agent increses the distance bteween the bodies from d to 2d .work done of external agent

Answer 1

Answer:

W.D=kd/r^2

Explanation:

W.D=F× displacement

W.D=k/r^2×(2d-d)

W.D=k/r^2×(d)

W.D=kd/r^2