the auditorium in a school is 15 metre wide and has a door and kaukauna student centres at 8:00 a.m. through the door and makes 10 rounds along the 15 metre wall back and forth and finally leaves the classroom at 9:30 through the same door compute the average speed and average velocity of the student
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Answer:
1/8 m/s average speed
0 m/s average velocity
Explanation:
Total distance covered = 15*10*2 = 300m
Total time taken = 1 : 30 hrs = 5400 seconds
Average speed = Total distance covered/ total time taken
Average speed = 300m/ 5400 sec = 1/8 m/s
Average velocity = Total displacement/ total time taken
Average velocity = 0 m/ 5400 sec = 0 m/s
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