the aum of first 20 natural number
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We have to find the sum n terms of the AP 1,2,3,...
Here
a=1,d=1.
Therefore, Required sum Sn=2n[2a+(n−1)d]=2n[2×1+(n−1)×1]
⇒Sn=2n[2+n−1]
⇒Sn=2n(n+1) ...(1)
Put n=20 in (1), we get
S20=220(20+1)=210
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