The auto rickshaw fare in a city is charged rupees 10 for the first kilometre and at the rate of Rs 4 per kilometre for subsequent distance covered. write the linear equation to express the above statement draw the graph of the linear equation.
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here is the answer
Let the total distance covered be x km
and, the total fare be Rs. y
Since, Total fare = fare for the first kilometer + fare for the remaining kilometer of distance ...........................(1)
We know that the fare for first kilometer is Rs. 10
Fare for the remaining kilometers i.e. (x - 1)
= 4(x - 1)
Put values in (1)
⇒ y = 10(1) + 4(x - 1)
⇒ y = 10 + 4x - 4
⇒ y = 4x + 6
When x = 0, we have, y = 4 × (0) + 6, So, y = 6
When x = - 1, we have, y = 4 × (- 1) + 6, = - 4 + 6
So, y = 2
When x = - 2, we have, y = 4 × (- 2) + 6 = - 8 + 6
So, y = - 2
x = 0 ; y = 6
x = - 1 ; y = 2
x = - 2 ; y = - 2
Now, you can draw the graph easily using the points I have given.
Now mark it as the brainliest answer
Let the total distance covered be x km
and, the total fare be Rs. y
Since, Total fare = fare for the first kilometer + fare for the remaining kilometer of distance ...........................(1)
We know that the fare for first kilometer is Rs. 10
Fare for the remaining kilometers i.e. (x - 1)
= 4(x - 1)
Put values in (1)
⇒ y = 10(1) + 4(x - 1)
⇒ y = 10 + 4x - 4
⇒ y = 4x + 6
When x = 0, we have, y = 4 × (0) + 6, So, y = 6
When x = - 1, we have, y = 4 × (- 1) + 6, = - 4 + 6
So, y = 2
When x = - 2, we have, y = 4 × (- 2) + 6 = - 8 + 6
So, y = - 2
x = 0 ; y = 6
x = - 1 ; y = 2
x = - 2 ; y = - 2
Now, you can draw the graph easily using the points I have given.
Now mark it as the brainliest answer
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