Question

The avarge boys of 15 years. If their ages aur in the ratio 3:5:7 find the age of youngest boy?

Answer 1

Let their ages be 'x'.

It is given that the average of the ages of the 3 boys is 15.

The ratio of their is 3:5:7.

=> (3x+5x+7x)/3 = 15

=> 15x/3 = 15

=> 5x = 15

=> x = 3

There ages will be:

3x = 3(3) = 9

5x = 5(3) = 15

7x = 7(3) = 21

Therefore, the age of the youngest boy is 9.