the average age of 30 students is 9 years if the age of their teacher is included it becomes 10 years ago the age of the teacher in years is
Answers
Answer:
Age of the teacher is 40 year.
Step-by-step explanation:
From the properties of average :
- Average = ( sum of quantities ) / ( number of quantities
Given,
Average age of 30 students is 9 year.
= > 9 year = ( sum of ages of 30 students ) / 30
= > 9 x 30 year = sum of ages of 30 students
= > 270 year = sum of ages of 30 students
According to the question : If the age of their teacher is included it becomes 10 years.
= > 10 year = ( sum of ages of students + age of teacher ) / 31
= > 10 x 31 year = 270 year + age of teacher
= > 310 year - 270 year = age of teacher
= > 40 year = age of teacher.
Hence, age of the teacher is 40 year.
Given :------
- Average of 30 boys of class = 9 years .
- After teacher age included new average = 10 years .
We have to Find age of Teacher ....?
Formula :------
Average is the Mean , Middle value of the number , it is Found by, when we divide all numbers sum by their number ...
Average = sum of observation / Total Number of observation ..
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Solution :--
it is given that average of 30 boys of class is 9 years.
Putting value in formula we get,
→ 9 = sum of age of all boys /30
(Cross - multiply) we get,
→ sum of age of all boys = 9 × 30 = 270 years..
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Now,
when Age of teacher also included , than Average becomes 10 years .
→ Total members now = (30 students + 1 teacher) = 31
Again,
→ 10 = sum of all members / 31
→ sum of all members = 10×31 = 310 years ..
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Now,
This is the age of 30 students + 1 teacher ,
and , we already have 30 students total age = 270 years.
Hence, Teacher age = 410 - 270 = 40 years ...
So, Age of Teacher was 40 years..
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★ Shortcut ★
→ [[[[ Teacher age = New average + (Increased Average × Number of Students ]]]]
Here ,
☛ New Average = 10 year
☛ Increased Average = 1 year
☛ Number of students = 30 .
Putting values we get,
➠ Teacher Age = 10 + 1 × 30 = 40 years ..
Hence, Teacher was 40 years old ...
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