The average age of A, B And C sis 30 years. If the difference between B’s age and A’s age is same as the difference between C’s age and B’s age . If D is 40 years older than B then what is the sum of the age B and D?
Answers
Answer:
sum of b and d = 40+30=70 years
The sum of the age of B and D is 100 years
Explanation:
Given Condition:
1. The average age of A, B, and C is 30 years
2. The difference between B’s age and A’s age is the same as the
difference between C’s age and B’s age.
3. D is 40 years older than B then what is the sum of the age B and D
To find:
The sum of the age B and D
STEP 1: Find the Average value
==> From the given condition 1,
==>Average= A+B+C /3 = 30
==> A+B+C = 30×3
==> A+B+C=90 ==> 1
STEP 2: Find the B value
==> From the condition2,
==> (B-A)=(C-B)
==> B-A=C-B
==> B+B = C+A
==> 2B = C+A
==> B = C+A/2 ==> 2
STEP 3:
==> Substitute equation 2 in 1
==> A+B+C=90
==> A+(C+A/2)+C =90
==> (2A+C+A+2C)/2=90
==> 2A+C+A+2C=90×2
==> 3A+3C = 180
==> 3(A+C)=180
==> A+C =180/3
==> A+C = 60 ==> 3
STEP 4:
==> Substitute equation 3 in equation 2
==> A+C/2 =B
==> 2B = A+C
==> 2B = 60
==> B = 60/2
==> B = 30 Years
STEP 5: Find the value of D
==> According to third condition
==> D = 40+B
==> We know that B is 30 years
==> D= 40+30
==> D = 70 years
STEP 5: Find the sum of B and D
==> B+D = 30+70
==> B+D = 100
The sum of the age of B and D is 100 years