Question

the average age of A, B and C whose age are intezers of x, y and z respectivaly 30. If the age of b is exactly 5 more than of A, what is the minimum possible value of z​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

minimum possible value of z = 1  if  age of B is exactly 5 more than of A and average age = 30 and ages are in integer

Step-by-step explanation:

age of A,B and C ,whose ages are integers x,y,z respectively

average age of A,B and C  = 30

=> 30 = (x  + y + z)/3

=> x + y + z  =  90

B is exactly 5 more than of A  

=> y = x + 5

=> x + x + 5 + z = 90

=> 2x + z  = 85

x minimum = 1  => z max  = 83

x maximum = 42 => z min = 1

x      y      z

1       6    83

-      -      -

42   47    1

minimum possible value of z = 1

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