the average age of A,B and C ,whose ages are integers x,y,z respectively,is 30 .if the age of B is exactly 5 more than of A,w hat is the minimum possible value of z?
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Answer:
The minimun value of z can be 15
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minimum possible value of z = 1 if age of B is exactly 5 more than of A and average age = 30 and ages are in integer
Step-by-step explanation:
age of A,B and C ,whose ages are integers x,y,z respectively
average age of A,B and C = 30
=> 30 = (x + y + z)/3
=> x + y + z = 90
B is exactly 5 more than of A
=> y = x + 5
=> x + x + 5 + z = 90
=> 2x + z = 85
x minimum = 1 => z max = 83
x maximum = 42 => z min = 1
x y z
1 6 83
- - -
42 47 1
minimum possible value of z = 1
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