Math, asked by silama, 3 months ago

The average age of A, B, C, and D is 60 years. The average age of b, C, D and E is 63years. If the total age of A and E is 21:25 What is the ratio, then what is the age of these two ?​

Answers

Answered by Anonymous
39

Question :-

The average age of A, B, C, and D is 60 years. The average age of b, C, D and E is 63years. If the total age of A and E is 21:25 What is the ratio, then what is the age of these two ?

Solution :-

Total age of A, B, C and D = 60 × 4 = 240 years

Total age B, C , D and E = 63 × 4 = 252 years

Now

( B + C + D + E ) - ( B + C + D + A ) = 252 -240 = 12

Or,

E - A = 12

Let be A = 21 x , So E = 25 x

∴ 25x - 21 x = 12

∴ 4x = 12

∴ x = 12÷ 4 = 3

∴ Age of A = 21 x = 21 × 3 = 63 years

And age of E = 25 x = 25 × 3 = 75 years

By the question ,

E - A = 4 × 63 - 4 × 60 = 252 - 240 = 12

E : A = 25 : 21

∴ E - A = : 4

∴ : 1 → 3

∴ E → 25 × 3 = 75 years

A → 21 × 3 = 63 years

Answer :-

Age of A = 63 years

Age of E = 75 years

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