Question

The average age of a group of workers is 42 years. If eight new workers of average age 36 years join the group, the average age of the group becomes 40 years. How many workers were there in the group initially?

Answer 1

Answer:

39 this is the ans i think

Answer 2

Answer:

Step-by-step explanation:

$(x1+x2+...+xn)/n=42$ this means $x1+x2+...+xn=42n$=sum1

$(a1+a2+...a8)/8=255$  this means  $a1+a2+..a8=36$ = Sum2

$(sum1+sum2)/n+8=40$

$(42n+288)/n+8=40$

$42n+288=40n+320$

$so, by shifting you get\\n=16$