Question

The average age of a man and his daughter is 19 years. The ratio of their ages is 16:3. What is the difference between the ages of father and daughter after 6 years

Answer 1

Answer :

19 * 2 = 38

38/ ( 16 + 3 )= 2

Daughter : 2* 3= 6

Father:   2 * 16 = 32

Difference : ( 32+ 6 ) - ( 6 + 6) = 26

Answer 2

The required difference is 26 years.

Step-by-step explanation:

Since we have given that

Average age of a man and his daughter = 19 years

So, it becomes,

$M+D=19\times 2=38$

Ratio of their ages = 16:3

So, it becomes,

$16x+3x=38\\\\19x=38\\\\x=\dfrac{38}{19}\\\\x=2$

So, Difference between the ages of father and daughter after 6 years would be

$16x+6-(3x+6)\\\\=16x+6-3x-6\\\\=13x\\\\=13\times 2\\\\=26$

Hence, the required difference is 26 years.

# learn more:

A man is four times his daughter after 6 years he will be twice of his daughter age find the age of daughter and father​

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