Question

The average age of a man and his son is 33 years. The ratio of their ages is 8 :3 respectively. What is the man's age?

Answer 1

Answer:

• The man's age = 48 years.

Given :

• Average age of a man and his son = 33 years.

• The ratio of their ages is 8 :3 respectively.

To find :

• The man's age =?

Step-by-step explanation:

Average age of a man and his son = 33 years.

[Given]

Let, the age of man be 8x.

Then, the age of his son be 3x.

According to the question :

Average = (sum of both age) /2

Substituting the values, we get,

➻ 33 = (8x + 3x) /2

➻ 33 × 2 = 11x

➻ 66 = 11x

Or, 11x = 66

➻ x = 66/11

➻ x = 6

Hence,

The man's age = 8x ⟹ 8 × 6 = 48 years.

Answer 2

Given:

• Average age of a man and his son = 33 years.
• The ratio of their ages is 8 :3 respectively.

To find :

The man's age =?

Solution:

let the age of man be 8x and son be 3x

A/q

(Average age = sum of both age )/ 2

33 = 8x + 3x / 2

33 × 2 = 11 x

11x = 66

x = 66/ 11

x = 6

Hence , the age of man = 8 × 6 = 48 yrs.