Question

The average age of a man and his son is 40 years. The ratio of their ages is 11 : 5 respectively. What is the
son's age?
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Answer 1

Answer:

ANSWER IS 40.

Step-by-step explanation:

LET AGES OF THE FATHER AND THE SON BE 11x & 5x.

Average of their ages = (11x + 5x)/2

= 16x/2

= 8x

As average of their ages is 40.

THEN,

8x=40

x=5

Age of the father = 11×5= 55

Age of the son = 5×5=25

Answer 2

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Average age of man and his son = 40 years

Let the ratio of thier ages be x

Age of Man = 11x

Age of Son = 5x

A•T•Q,

$\implies \frac{11x + 5x}{2} = 40$

$\implies \frac{16x}{2} = 40$

$\implies 16x = 40 \times 2$

$\implies 16x = 80$

$\implies x = \frac{80}{16}$

$\implies x = \frac{ \cancel{80}}{ \cancel{16}}$

$\implies x = 5$

Hence ,

Age of Man

= 11x

= 5×11

= 55

Age of Son

= 5x

= 5×5

= 25

HØPÈ ÏT HÊLPS ♠♦♠