Question

The average age of a twelve-member team is the same as it was 4 years ago, because an old
member has been replaced by a young member. If the age of older member is 65 What is the
age of young member?
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Answer 1

Answer:

years back sum of 10 members is 10x

Present

Let y is age of replaced candidate

9(x+4)+y =10x

9x+36+y=10x

36+y=x

So old person is replaced by 36+4=40years younger

Answer 2

Answer:

The younger members' age is $17$ years.

Explanation:

• The average age is the sum of every age divided through the entire matter of a long time.
• The cost of the common variety lies halfway among all of the values.
• In the past, a person for a long time gets decreased through a selected variety of years.

The average is calculated as:

$X=\frac{(x + x2 +x3 +....xn)}{n}$

where $x1, x2, x3,...,xn$ are the individual values

           $n$ is the count.

Step 1:

At present time:

Let $Y$ be the sum of $11$ members.

Let $a$ be the young member's age.

So, $\frac{Y +a}{12} = Average$ $Age$

We consider $4$ years ago:

$\frac{Y-(11*4) + (65-4)}{12} = Average$ $Age$

Step 2:

According to the question:

$\frac{Y +a}{12} = \frac{Y-(11*4) + (65-4)}{12}$

$Y +a = Y-(11*4) + (65-4)$

$a =-(11*4) + (65-4)$

$a =17$ years

So, the younger members' age is $17$ years.