The average age of my family consisting of my parents & myself is 30 yrs . 10 years ago, the average age of my parents were 23 yrs. Find my present age
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let my age be x, my father's age be y, and mother's age z.
Average age is 30
so, (x+y+z)/3 = 30
hence, x+y+z = 90
10 years ago, parent's average qas 23
so,(y+z-20)/2 = 23
hence, (y+z-20)= 66
i.e. y+z = 86
putting y+z = 86 in first condition
x+86 = 90
so, x( my age) is 4 years
Average age is 30
so, (x+y+z)/3 = 30
hence, x+y+z = 90
10 years ago, parent's average qas 23
so,(y+z-20)/2 = 23
hence, (y+z-20)= 66
i.e. y+z = 86
putting y+z = 86 in first condition
x+86 = 90
so, x( my age) is 4 years
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Please watch out the pic. I've solved it.
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Anonymous:
My mistake plz report it.
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