Math, asked by tasleemsiddiqu6513, 1 year ago

The average age of three boys is 15 years and their ages are in proportion 3:5:7. what is the age in years of the youngest boy


tushargargacc6p8csyi: answer is 3,5,7 young age is 3
tushargargacc6p8csyi: 15* 3/3+5+7 = 3
tushargargacc6p8csyi: aisekarke sari age nikal lo

Answers

Answered by Anonymous
65
⭐⭐Hello friend..Ur answer is here⤵⤵

⚫ 3:5:7

Let the ages of boys are 3x,5x and 7x

➡Average=3x+5x+7x/3=15

➡ 15x/3=15

➡ 5x=15

➡ x=3

So the age of youngest boy is 3x=3×3=9 year

I HOPE IT IS HELPFUL TO YOU ☺
Answered by SerenaBochenek
14

Answer:

The age of youngest boy is 9 yrs.

Step-by-step explanation:

Given the ages of 3 boys in proportion 3:5:7 and also their average age is 15. we have to find the age of youngest boy.

Let the ages of 3 boys are

3x, 5x and 7x

Average is calculated by the sum divided by the count. Average of three numbers is given by the sum of the three numbers divided by three.

Average=\frac{3x+5x+7x}{3}

15=5x

x=3

The age of youngest boy is 3x=3(3)=9 yrs.

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