The average age of three boys is 15 years and their average in proportion 3:5:7, what is the age in years of the youngest boy?
Answers
Answered by
0
Answer:
let the age be 3x, 5x and 7x
average age is 15 then
3x+5x+7x=15
15x=15
x=15/15
x=1
the age of the youngest is 7x
since 7×1=7 year
Answered by
2
Answer:
9 years
Step-by-step explanation:
average of three boys age = 15
therefore total age of three boys = 15×3= 45
therefore 3x + 5x + 7x = 45
15x = 45
x = 3
therefore three boys ages = 1) 3×3= 9 years
2) 5×3= 15 years
3) 7×3= 21 years
therefore youngest boys year is 9.
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