The average age of two individuals is 45 years. If the first person is 50, what is the age of the second?
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How to Solve Problems on Ages?
- How to Solve Problems on Ages?Age after n years = X + n.
- How to Solve Problems on Ages?Age after n years = X + n.Age n years ago = X – n.
- How to Solve Problems on Ages?Age after n years = X + n.Age n years ago = X – n.n times the present age = nX.
- How to Solve Problems on Ages?Age after n years = X + n.Age n years ago = X – n.n times the present age = nX.If ages in the numerical are mentioned in the ratio A:B, then A:B will be AX and BX.
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The average age of two individuals is 45 years. If the first person is 50, what is the age of the second?
Given:
The average age of 5 men = 45 years
The average age of another 4 men = 36 years
Formula Used:
Average = sum of the age of men/number of men
Calculations:
Sum of the ages of 5 men = 45 × 5 = 225
Sum of the ages of another 4 men = 36 × 4 = 144
Sum of the ages of 9 men = sum of the ages of 5 men + sum of the ages of 4 men
⇒ 225 + 144 = 369
Number of men = 9
Average of 9 men = 369 ÷ 9
⇒ 41 years
∴ The mean age of all these 9 men will be equal to 41 years
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