Question

The average (arithmetic mean) of 4 different integers is 75. If the largest integer is 90, what is the least possible value of the smallest integer?

Answer 1

Answer:

Suppose four different integers are : a,b,c & d.The average of these four different integers is :

AvgAvg = (a+b+c+d)/4 = 75

=>

Sum of these four different integers is : sum = a+b+c+d = 300

The difference between the largest integer and the average is : 90-75 = 15

if largest integer is 90 (suppose d=90) then a+b+c = 300-90 = 210

=> Average of a,b & c is : (a+b+c)/3 = 210/3 = 70

Step-by-step explanation:

pls mark brainliest