Question

The average arithmetic mean) weight of five students is 150.4 pounds. If no students weighs less than 130 pounds and if no two students weights are within 5 pounds of each other, what is the most in pounds, any one of the students can weigh?​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given  The average arithmetic mean) weight of five students is 150.4 pounds. If no students weighs less than 130 pounds and if no two students weights are within 5 pounds of each other, what is the most in pounds, any one of the students can weigh?

•   Given average weight of 5 students is 150.4 pounds.
•    No student weighs less than 130 pounds
•      Also no two students weights are within 5 pounds of each other
•   We need to find the most in pounds that anyone of the students can weigh.
• Now the lowest weight is 130 pounds and if the student weighs 130 pounds then, assuming that the other three are 135, 140, 145  
• Let the fifth person be P
•      So 130 + 135 + 140 + 145 + P / 5 = 150.4
•                         550 + P / 5 = 150.4
•                          550 + P = 150.4 x 5
•                            550 + P = 752
•                               Or P = 202 pounds

Reference link will be

https://brainly.com/question/4531258