Question

The average atomic mass of a mixture containing 79 mole % of 24Mg and remaining 21 mole % of 25Mg and 26Mg , is 24.31. % mole of 26Mg is : (A) 5 (B) 20 (C) 10 (D) 15 expain in easy and detail warana r4eport your answer

Answer 1

Answer:

Molecular mass=∑x

i

M

i

x

i

=Fraction of the isotope

M

i

=Mass of the isotope

∴24.31=0.79×24+x×25+y×26...........(1)

Also x+y+0.79=1.00⇒x+y=0.21...........(2)

On solving equation 1 and 2 we get,

∴x=0.11 & y=0.10

Thus mole % of

26

Mg is 10%

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