The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of
isotopes 8X
16 and 8X
18 in the sample
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Correct Question :-
The average atomic mass of a sample of an element X is 16.2u. What are the percentages of isotopes ¹⁶₈X and ¹⁸₈X in the sample?
Answer :-
Given :
- Average atomic mass of a sample element X = 16.2u.
To find :
- Percentages of isotopes ¹⁶₈X and ¹⁸₈X
Solution :
Let the percentage of ¹⁶₈X is y%.
Then,
Percentage of ¹⁸₈X is (100-y)%.
Given that average atomic mass of sample is 16.2.Therefore,
→16×(y/100) + 18(100-y)/100 = 16.2
→16y + 18(100-y) / 100 = 16.2
→16y + 18(100-y) = 1620
→16y + 1800 - 18y = 1620
→1800 - 2y = 1620
→1800 - 1620 = 2y
→180 = 2y
→y = 180/2
→y = 90%
We have,
- Percentage of ¹⁸₈X is (100-y)%
Therefore,
Percentage of ¹⁸₈X :
→100 - y
→100 - 90
→10%
Hence,
The percentages of isotopes are 90% & 10%.
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