Question

The average atomic mass of a sample of an element X is 16.2u. What are the percentages of isotopes 16 8X & 18 8X in the sample. .

Answer 1

Answer:

$\bf\red{ =16 (x) + 18( 1 - x) = 16.2}$

$= 16x + 18 - 18x = 16.2$

$= 2x = 18 - 16.2$

$x = 0.9$

$16 x_{8} = 90\%$

$\bf\blue{18 x_{8} = 10\%}$

Hope it will be helpful :)....✍️

Answer 2

Answer:

=10% do isotopes.

It is given that the average atomic mass of the sample of element X is 16.2 u. Let the percentage of isotope 8 18 X be y%. Thus, the percentage of isotope 8 16 X will be (100 − y)%. Therefore, the percentage of isotope 8 18 X is 10%.l