Question

the average atomic mass of a sample of an element X is 16.2u. what is the percentage of isotope ¹⁶X and ¹⁸x in the sample.​

Answer 1

Answer:

16.2=$\frac{(x*16)+([100-x]*18)}{100}$

1620=16x-18x+1800

1620-1800=-2x

-180=-2x

x=180/2

x=90%

100-x=10%