THE AVERAGE ATOMIC MASS OF AN SAMPLE OF AN ELEMENT X IS 16.2 U, WHAT ARE THE PERCENTAGE OF ISOTOPS 816X AND 8 18X IN THE SAMPLE
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Lets take the percentage of the isotope of 16 8 X as --> x %
So , the percentage of the isotope of 18 8X ---> (100 - x) %
We are given the average atomic mass as 16.2
× 16 + × 18 = 16.2
+ = 16.2
-2x + 1800 = 16.2 × 100
-2x + 1800 = 1620
-2x = 1620 - 1800
-2x = -180
x =
x = 90 %
Therefore , percentage of isotope of 16 8 X = 90 %
percentage of isotope of 18 8 X = 100 - x = 100 - 90 = 10 %
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