Chemistry, asked by ShreyaKachawe, 5 months ago

The average atomic mass of boron is 10.8 u. If the isotopic mass of B-10 is 10.013 and that of B-11 is 11.009, then the relative abundance of these isotopes is respectively

(A) 80.1% and 19.9%

(B) 11% and 89%

(C) 20.98% and 79.02%

(D) 10.001% and 89.9%​

Answers

Answered by padmavathibolla
9

Answer:

In nature, the element boron occurs 19.9% as 10B and 80.1% as 11B. If the isotopic mass of 10B is 10.013 amu and that of 11B is 11.009 amu, the atomic mass of boron is 80.1% and 19.9%

so, the answer is 80.1% and 19.9%

option (A)

MARK ME AS A BRAINLIST

I HOPE THIS ANSWER WILL HELPS YOU

Similar questions