The average atomic mass of element X is 16.2 u .If it occurs as two isotopes X-16 and X-18 find the % abundance of each isotope of X. Can you name element X.
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Let the percentage of ¹⁶8X be A%. Then the percentage of ¹⁸8X be (100-A)%.
therefore, 16×(A/100) + 18 × [(100-A) /100] = 16.2
=》1800-2A=1620
=》A=90
so the answer is 90% ¹⁶8X And 10% ¹⁸8X
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