The average bus fare of a student to travel to USP daily is $5.31. If the distribution of bus fares
is approximately normal with a standard deviation of $0.31, what is the probability that a
randomly selected bus fare is less than $4.50?
Answers
Answer:
Step-by-step explanation:
Given : The average bus fare of a student to travel to USP daily is $5.31. the distribution of bus fares is approximately normal with a standard deviation of $0.31,
To Find : the probability that a randomly selected bus fare is less than $4.50
Solution:
Mean = 5.31
SD = 0.31
Value = 4.5
Z score = ( Value - Mean ) /SD
=> Z score = ( 4.5 - 5.31) / 0.31
=> Z score = -0.81/0.31
=> Z score = -2.613
From z score table : 0.00447 = 0.447 %
probability that a randomly selected bus fare is less than $4.50 is 0.00447
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