Question

the average distance between the earth and moon is 3.84 × 10^5 km. If mass of the moon is 7.4×10^22 kg and that of earth is 6×10^24 kg, the gravitational force of the moon on the earth is​

Answer 1

HI DEAR SHRESTA HERE PLS SEE THE ANSWER AND THANK MY ANSWER TOO...

$Given \: that,$

$Mass \: of \: the \: Earth  \: m1=6 \: × \: {10}^{24}$

$Mass \: of \: the \: Moon  \: m2=7.4× {10}^{22} kg$

$Distance \: between \: the \: Earth \: and \: the \: Moon  \: d=3.84× {10}^{5} km=3.84× {10}^{8} m$

$Gravitational \: Constant  \: G=6.7 \times {10}^{ - 11} Nm2/kg2</p><p></p><p></p><p>$

$Now, \: by \: using \: Newton’s \: law \: of \: gravitation</p><p></p><p>  F \: =gm1m2 \div {r}^{2} </p><p></p><p></p><p>$

$F=(3.84× {10}^{8} )26.7×1 {10}^{ - 11} ×6× {10}^{24} ×7.4× {10}^{22} \div {(3.84 \times {10}^{8}) }^{2} </p><p>$

$F=20.069× {10}^{19}$

Answer 2

Answer:

Mass of earth = 6 × 10²⁴ kg

Mass of moon = 7.4 × 10²² kg

Distance between them = 3.84 × 10⁵ km = 3.84  × 10⁸ m

We have value of G = 6.7 × 10⁻¹¹ N m² kg⁻²

We have to find force :

We have :

F = G m₁ m₂ / r²

F = ( 6.7 × 10⁻¹¹ ) ( 6 × 10²⁴ ) ( 7.4 × 10²² ) / (  3.84 × 10⁸ )² N

F = 20.2 × 10¹⁹ N

Explanation: