Question

the average distance between the electron and central proton in a hydrogen atom is 5.3×10^-12 m. what is the magnitude of average electrostatic force between these two particles?
1) 9.2× 10^6N
2) 10.8× 10^5N
3) 8.2×10^-6N
4) 9×10^-7​

Answer 1

Given :

➠ Distance b/w electron and proton = 5.3 × $10^{-12}$m

To Find :

➔ Magnitude of electrostatic force b/w these two particles.

SoluTion :

⇒ The magnitude of electrostatic force between two point charges is directly proportional to the product of charges and inversely proportional to the square of the distance between them. This is known as coulomb's law also known as inverse square law.

$\leadsto\sf\:F=\dfrac{kq_1q_2}{r^2}$

$\leadsto\sf\:F=\dfrac{(9\times 10^9)\times (1.6\times 10^{-19})^2}{(5.3\times 10^{-12})^2}$

$\leadsto\sf\:F=\dfrac{23.04\times 10^{-29}}{28.09\times 10^{-24}}$

$\leadsto\boxed{\bf{F=8.2\times 10^{-6}\:N}}$